27u^2-15u=0

Solution for 27u^2-15u=0 equation:

27u^2-15u=0

a = 27; b = -15; c = 0;
Δ = b2-4ac
Δ = -152-4·27·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-15}{2*27}=\frac{0}{54}
=0
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+15}{2*27}=\frac{30}{54}
=5/9
$